Brandon and Cody had $720 altogether. Cody gave
25 of his money to Brandon. After that, Brandon gave
35 of his money to Cody. In the end, Brandon had
16 of the total sum of money. How much did Brandon have at first?
| |
Cody |
Brandon |
Total |
| Before 1 |
5 p |
? |
$720 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$720 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$720 |
Comparing between
Cody and Brandon
in the end |
5x2 =
10 u |
1x2 =
2 u |
$720 |
The amount that Brandon had in the end is the repeated. Make the amount that Brandon had in the end the same. LCM of 2 and 1 is 2.
12 u = 720
1 u = 720 ÷ 12 = 60
5 u = 5 x 60 = 300
3 p = 720 - 300 = 420
1 p = 420 ÷ 3 = 140
Amount that Cody had at first
= 5 p
= 5 x 140
= $700
Amount that Brandon had at first
= 720 - 700
= $20
Answer(s): $20
