Tim and Michael had $612 altogether. Michael gave
25 of his money to Tim. After that, Tim gave
35 of his money to Michael. In the end, Tim had
16 of the total sum of money. How much did Tim have at first?
| |
Michael |
Tim |
Total |
| Before 1 |
5 p |
? |
$612 |
| Change 1 |
- 2 p |
+ 2 p |
|
| After 1 |
3 p |
5 u |
|
| Before 2 |
3 p |
5x1 =
5 u |
$612 |
| Change 2 |
+ 3x1 =
+ 3 u |
- 3x1 =
- 3 u |
|
| After 2 |
|
2x1 =
2 u |
$612 |
Comparing between
Michael and Tim
in the end |
5x2 =
10 u |
1x2 =
2 u |
$612 |
The amount that Tim had in the end is the repeated. Make the amount that Tim had in the end the same. LCM of 2 and 1 is 2.
12 u = 612
1 u = 612 ÷ 12 = 51
5 u = 5 x 51 = 255
3 p = 612 - 255 = 357
1 p = 357 ÷ 3 = 119
Amount that Michael had at first
= 5 p
= 5 x 119
= $595
Amount that Tim had at first
= 612 - 595
= $17
Answer(s): $17
