At a tourist attraction, each adult ticket cost $35 and each child ticket cost $12. On Monday, the number of adult tickets sold was 80 less than the number of child tickets. On Tuesday, the number of adult tickets sold decreased by 35% while the number of child tickets sold increased by 50%. If a total of 1410 tickets were sold on Tuesday, how much money was collected on Monday?
|
Adult tickets |
Child tickets |
Total tickets |
Before |
1 u |
1 u + 80 |
2 u + 80 |
Change |
- 0.35 u |
+ 0.5 u + 40 |
|
After |
0.65 u |
1.5 u + 120 |
2.15 u + 120 |
35% x 1 u =
35100 x 1 u = 0.35 u
50% x 1 u =
50100 x 1 u = 0.5 u
50% x 80 =
50100 x 80 = 40
Number of tickets sold on Tuesday
= 0.65 u + 1.5 u + 120
= 2.15 u + 120
2.15 u + 120 = 1410
2.15 u = 1410 - 120
2.15 u = 1290
1 u = 1290 ÷ 2.15 = 600
Amount collected from adult tickets on Monday
= 1 u x 35
= 600 x 35
= $21000
Amount collected from child tickets on Monday
= 12(1 u + 80)
= 12(600 + 80)
= 12 x 680
= $8160
Total amount collected on Monday
= 21000 + 8160
= $29160
Answer(s):$29160