At a tourist attraction, each adult ticket cost $27 and each child ticket cost $10. On Thursday, the number of adult tickets sold was 172 less than the number of child tickets. On Friday, the number of adult tickets sold decreased by 40% while the number of child tickets sold increased by 50%. If a total of 1518 tickets were sold on Friday, how much money was collected on Thursday?
|
Adult tickets |
Child tickets |
Total tickets |
Before |
1 u |
1 u + 172 |
2 u + 172 |
Change |
- 0.4 u |
+ 0.5 u + 86 |
|
After |
0.6 u |
1.5 u + 258 |
2.1 u + 258 |
40% x 1 u =
40100 x 1 u = 0.4 u
50% x 1 u =
50100 x 1 u = 0.5 u
50% x 172 =
50100 x 172 = 86
Number of tickets sold on Friday
= 0.6 u + 1.5 u + 258
= 2.1 u + 258
2.1 u + 258 = 1518
2.1 u = 1518 - 258
2.1 u = 1260
1 u = 1260 ÷ 2.1 = 600
Amount collected from adult tickets on Thursday
= 1 u x 27
= 600 x 27
= $16200
Amount collected from child tickets on Thursday
= 10(1 u + 172)
= 10(600 + 172)
= 10 x 772
= $7720
Total amount collected on Thursday
= 16200 + 7720
= $23920
Answer(s):$23920