At a tourist attraction, each adult ticket cost $29 and each child ticket cost $11. On Thursday, the number of adult tickets sold was 140 less than the number of child tickets. On Friday, the number of adult tickets sold decreased by 20% while the number of child tickets sold increased by 40%. If a total of 1516 tickets were sold on Friday, how much money was collected on Thursday?

	Adult tickets	Child tickets	Total tickets
Before	1 u	1 u + 140	2 u + 140
Change	- 0.2 u	+ 0.4 u + 56
After	0.8 u	1.4 u + 196	2.2 u + 196

20% x 1 u = ²⁰₁₀₀ x 1 u = 0.2 u 
40% x 1 u = ⁴⁰₁₀₀ x 1 u = 0.4 u
40% x 140 = ⁴⁰₁₀₀ x 140 = 56

Number of tickets sold on Friday
= 0.8 u + 1.4 u + 196
= 2.2 u + 196

2.2 u + 196 = 1516
2.2 u = 1516 - 196
2.2 u = 1320

1 u = 1320 ÷ 2.2 = 600

Amount collected from adult tickets on Thursday
= 1 u x 29
= 600 x 29
= $17400

Amount collected from child tickets on Thursday
= 11(1 u + 140)
= 11(600 + 140)
= 11 x 740
= $8140

Total amount collected on Thursday
= 17400 + 8140
= $25540

Answer(s):$25540