At a stadium, each adult ticket cost $26 and each child ticket cost $9. On Thursday, the number of adult tickets sold was 60 less than the number of child tickets. On Friday, the number of adult tickets sold decreased by 40% while the number of child tickets sold increased by 5%. If a total of 558 tickets were sold on Friday, how much money was collected on Thursday?
|
Adult tickets |
Child tickets |
Total tickets |
Before |
1 u |
1 u + 60 |
2 u + 60 |
Change |
- 0.4 u |
+ 0.05 u + 3 |
|
After |
0.6 u |
1.05 u + 63 |
1.65 u + 63 |
40% x 1 u =
40100 x 1 u = 0.4 u
5% x 1 u =
5100 x 1 u = 0.05 u
5% x 60 =
5100 x 60 = 3
Number of tickets sold on Friday
= 0.6 u + 1.05 u + 63
= 1.65 u + 63
1.65 u + 63 = 558
1.65 u = 558 - 63
1.65 u = 495
1 u = 495 ÷ 1.65 = 300
Amount collected from adult tickets on Thursday
= 1 u x 26
= 300 x 26
= $7800
Amount collected from child tickets on Thursday
= 9(1 u + 60)
= 9(300 + 60)
= 9 x 360
= $3240
Total amount collected on Thursday
= 7800 + 3240
= $11040
Answer(s):$11040