Brandon and Fred started jogging from the same point. Fred started jogging 10 minutes earlier than Brandon. Brandon's jogging speed was 400 m/min and Fred's jogging speed was 200 m/min. They went in the same direction and did not change their speeds throughout.
- How long did it take for Brandon to catch up with Fred?
- What distance would Fred have jogged when Brandon caught up with him? Express your answer in meters.
|
Brandon |
Fred |
Speed |
400 m/min |
200 m/min |
Start time |
|
10 min earlier |
Extra distance covered at first |
|
2000 m |
(a)
Distance that Fred covered when he jogged 10 minutes earlier
= 10 x 200
= 2000 m
Distance that Brandon covered more than Fred per min
= 400 - 200
= 200 m
Time that Brandon needed to take to cover the additional 2000 m
= 2000 ÷ 200
= 10 min
(b)
Time that Fred would had jogged when Brandon caught up with him
= 10 + 10
= 20 min
Distance that Fred would have jogged when Brandon caught up with him
= 20 x 200
= 4000 m
Answer(s): (a) 10 min; (b) 4000 m