Peter and Jack started jogging from the same point. Jack started jogging 6 minutes earlier than Peter. Peter's jogging speed was 400 m/min and Jack's jogging speed was 200 m/min. They went in the same direction and did not change their speeds throughout.

1. How long did it take for Peter to catch up with Jack? 
2. What distance would Jack have jogged when Peter caught up with him?  Express your answer in meters.

	Peter	Jack
Speed	400 m/min	200 m/min
Start time		6 min earlier
Extra distance covered at first		1200 m

(a)
Distance that Jack covered when he jogged 6 minutes earlier
= 6 x 200
= 1200 m

Distance that Peter covered more than Jack per min
= 400 - 200
= 200 m

Time that Peter needed to take to cover the additional 1200 m
= 1200 ÷ 200
= 6 min

(b)
Time that Jack would had jogged when Peter caught up with him
= 6 + 6
= 12 min

Distance that Jack would have jogged when Peter caught up with him
= 12 x 200
= 2400 m

Answer(s): (a) 6 min; (b) 2400 m