Lee and Neave started jogging from the same point. Neave started jogging 2 minutes earlier than Lee. Lee's jogging speed was 400 m/min and Neave's jogging speed was 300 m/min. They went in the same direction and did not change their speeds throughout.
- How long did it take for Lee to catch up with Neave?
- What distance would Neave have jogged when Lee caught up with him? Express your answer in meters.
|
Lee |
Neave |
Speed |
400 m/min |
300 m/min |
Start time |
|
2 min earlier |
Extra distance covered at first |
|
600 m |
(a)
Distance that Neave covered when he jogged 2 minutes earlier
= 2 x 300
= 600 m
Distance that Lee covered more than Neave per min
= 400 - 300
= 100 m
Time that Lee needed to take to cover the additional 600 m
= 600 ÷ 100
= 6 min
(b)
Time that Neave would had jogged when Lee caught up with him
= 6 + 2
= 8 min
Distance that Neave would have jogged when Lee caught up with him
= 8 x 300
= 2400 m
Answer(s): (a) 6 min; (b) 2400 m