Caden and Lee started jogging from the same point. Lee started jogging 10 minutes earlier than Caden. Caden's jogging speed was 450 m/min and Lee's jogging speed was 200 m/min. They went in the same direction and did not change their speeds throughout.
- How long did it take for Caden to catch up with Lee?
- What distance would Lee have jogged when Caden caught up with him? Express your answer in meters.
|
Caden |
Lee |
Speed |
450 m/min |
200 m/min |
Start time |
|
10 min earlier |
Extra distance covered at first |
|
2000 m |
(a)
Distance that Lee covered when he jogged 10 minutes earlier
= 10 x 200
= 2000 m
Distance that Caden covered more than Lee per min
= 450 - 200
= 250 m
Time that Caden needed to take to cover the additional 2000 m
= 2000 ÷ 250
= 8 min
(b)
Time that Lee would had jogged when Caden caught up with him
= 8 + 10
= 18 min
Distance that Lee would have jogged when Caden caught up with him
= 18 x 200
= 3600 m
Answer(s): (a) 8 min; (b) 3600 m