Pierre and Wesley started jogging from the same point. Wesley started jogging 6 minutes earlier than Pierre. Pierre's jogging speed was 250 m/min and Wesley's jogging speed was 100 m/min. They went in the same direction and did not change their speeds throughout.

1. How long did it take for Pierre to catch up with Wesley? 
2. What distance would Wesley have jogged when Pierre caught up with him?  Express your answer in meters.

	Pierre	Wesley
Speed	250 m/min	100 m/min
Start time		6 min earlier
Extra distance covered at first		600 m

(a)
Distance that Wesley covered when he jogged 6 minutes earlier
= 6 x 100
= 600 m

Distance that Pierre covered more than Wesley per min
= 250 - 100
= 150 m

Time that Pierre needed to take to cover the additional 600 m
= 600 ÷ 150
= 4 min

(b)
Time that Wesley would had jogged when Pierre caught up with him
= 4 + 6
= 10 min

Distance that Wesley would have jogged when Pierre caught up with him
= 10 x 100
= 1000 m

Answer(s): (a) 4 min; (b) 1000 m