Neave and Paul started jogging from the same point. Paul started jogging 6 minutes earlier than Neave. Neave's jogging speed was 450 m/min and Paul's jogging speed was 350 m/min. They went in the same direction and did not change their speeds throughout.
- How long did it take for Neave to catch up with Paul?
- What distance would Paul have jogged when Neave caught up with him? Express your answer in meters.
|
Neave |
Paul |
Speed |
450 m/min |
350 m/min |
Start time |
|
6 min earlier |
Extra distance covered at first |
|
2100 m |
(a)
Distance that Paul covered when he jogged 6 minutes earlier
= 6 x 350
= 2100 m
Distance that Neave covered more than Paul per min
= 450 - 350
= 100 m
Time that Neave needed to take to cover the additional 2100 m
= 2100 ÷ 100
= 21 min
(b)
Time that Paul would had jogged when Neave caught up with him
= 21 + 6
= 27 min
Distance that Paul would have jogged when Neave caught up with him
= 27 x 350
= 9450 m
Answer(s): (a) 21 min; (b) 9450 m