Lee and Luis started jogging from the same point. Luis started jogging 6 minutes earlier than Lee. Lee's jogging speed was 250 m/min and Luis's jogging speed was 150 m/min. They went in the same direction and did not change their speeds throughout.
- How long did it take for Lee to catch up with Luis?
- What distance would Luis have jogged when Lee caught up with him? Express your answer in meters.
|
Lee |
Luis |
Speed |
250 m/min |
150 m/min |
Start time |
|
6 min earlier |
Extra distance covered at first |
|
900 m |
(a)
Distance that Luis covered when he jogged 6 minutes earlier
= 6 x 150
= 900 m
Distance that Lee covered more than Luis per min
= 250 - 150
= 100 m
Time that Lee needed to take to cover the additional 900 m
= 900 ÷ 100
= 9 min
(b)
Time that Luis would had jogged when Lee caught up with him
= 9 + 6
= 15 min
Distance that Luis would have jogged when Lee caught up with him
= 15 x 150
= 2250 m
Answer(s): (a) 9 min; (b) 2250 m