Sarah had some chikoos and kiwis in 2 crates. In Crate W, the number of chikoos to the number of kiwis was in the ratio of 5 : 8. In Crate X, there were thrice as many chikoos as kiwis. After Sarah transferred
34 of the kiwis from Crate W to Crate X, the number of fruits left in Crate W was 133 and the ratio of the number of chikoos to the number of kiwis in Crate B became 2 : 7. How many fruits were in Crate X in the end?
|
Crate W |
Crate X |
|
Chikoos |
Kiwis |
Chikoos |
Kiwis |
Before |
5 u |
8 u |
3x2 = 6 p |
1x2 = 2 p |
Change |
|
- 6 u |
|
+ 6 u (+ 19 p) |
After |
5 u |
2 u |
2x3 = 6 p |
7x3 = 21 p |
Number of kiwis that Sarah transferred from Crate W to Crate X
=
34 x 8 u
= 6 u
Total number of fruits in Crate W in the end
= 5 u + 2 u
= 7 u
7 u = 133
1 u = 133 ÷ 7 = 19
The number of chikoos in Crate X is the unchanged quantity.
LCM of 3 and 2 is 6.
Number of kiwis that Sarah transferred from Crate W to Crate X
= 6 u
= 6 x 19
= 114
Increase in the number of kiwis that due to the transfer from Crate W to Crate X
= 21 p - 2 p
= 19 p
19 p = 6 u
19 p = 114
1 p = 114 ÷ 19 = 6
Number of fruits in Crate X in the end
= 6 p + 21 p
= 27 p
= 27 x 6
= 162
Answer(s): 162