Winnie had some starfruits and persimmons in 2 cartons. In Carton H, the number of starfruits to the number of persimmons was in the ratio of 2 : 9. In Carton J, there were twice as many starfruits as persimmons. After Winnie transferred ¹₃ of the persimmons from Carton H to Carton J, the number of fruits left in Carton H was 320 and the ratio of the number of starfruits to the number of persimmons in Carton B became 3 : 4. How many fruits were in Carton J in the end?

	Carton H		Carton J
	Starfruits	Persimmons	Starfruits	Persimmons
Before	2 u	9 u	2x3 =  6 p	1x3 = 3 p
Change		- 3 u		+ 3 u (+ 5 p)
After	2 u	6 u	3x2 = 6 p	4x2 = 8 p

Number of persimmons that Winnie transferred from Carton H to Carton J
= ¹₃ x 9 u
= 3 u

Total number of fruits in Carton H in the end
= 2 u + 6 u
= 8 u

8 u = 320
1 u = 320 ÷ 8 = 40

The number of starfruits in Carton J is the unchanged quantity.
LCM of 2 and 3 is 6.

Number of persimmons that Winnie transferred from Carton H to Carton J
= 3 u
= 3 x 40
= 120

Increase in the number of persimmons that due to the transfer from Carton H to Carton J
= 8 p - 3 p
= 5 p

5 p = 3 u 
5 p = 120

1 p = 120 ÷ 5 = 24

Number of fruits in Carton J in the end
= 6 p + 8 p
= 14 p
= 14 x 24
= 336

Answer(s): 336