Cathy had some mangosteens and persimmons in 2 boxes. In Box V, the number of mangosteens to the number of persimmons was in the ratio of 3 : 10. In Box W, there were twice as many mangosteens as persimmons. After Cathy transferred
25 of the persimmons from Box V to Box W, the number of fruits left in Box V was 315 and the ratio of the number of mangosteens to the number of persimmons in Box B became 8 : 9. How many fruits were in Box W in the end?
|
Box V |
Box W |
|
Mangosteens |
Persimmons |
Mangosteens |
Persimmons |
Before |
3 u |
10 u |
2x4 = 8 p |
1x4 = 4 p |
Change |
|
- 4 u |
|
+ 4 u (+ 5 p) |
After |
3 u |
6 u |
8x1 = 8 p |
9x1 = 9 p |
Number of persimmons that Cathy transferred from Box V to Box W
=
25 x 10 u
= 4 u
Total number of fruits in Box V in the end
= 3 u + 6 u
= 9 u
9 u = 315
1 u = 315 ÷ 9 = 35
The number of mangosteens in Box W is the unchanged quantity.
LCM of 2 and 8 is 8.
Number of persimmons that Cathy transferred from Box V to Box W
= 4 u
= 4 x 35
= 140
Increase in the number of persimmons that due to the transfer from Box V to Box W
= 9 p - 4 p
= 5 p
5 p = 4 u
5 p = 140
1 p = 140 ÷ 5 = 28
Number of fruits in Box W in the end
= 8 p + 9 p
= 17 p
= 17 x 28
= 476
Answer(s): 476