Jen had some mangosteens and lemons in 2 boxes. In Box M, the number of mangosteens to the number of lemons was in the ratio of 4 : 9. In Box N, there were twice as many mangosteens as lemons. After Jen transferred
23 of the lemons from Box M to Box N, the number of fruits left in Box M was 189 and the ratio of the number of mangosteens to the number of lemons in Box B became 5 : 7. How many fruits were in Box N in the end?
|
Box M |
Box N |
|
Mangosteens |
Lemons |
Mangosteens |
Lemons |
Before |
4 u |
9 u |
2x5 = 10 p |
1x5 = 5 p |
Change |
|
- 6 u |
|
+ 6 u (+ 9 p) |
After |
4 u |
3 u |
5x2 = 10 p |
7x2 = 14 p |
Number of lemons that Jen transferred from Box M to Box N
=
23 x 9 u
= 6 u
Total number of fruits in Box M in the end
= 4 u + 3 u
= 7 u
7 u = 189
1 u = 189 ÷ 7 = 27
The number of mangosteens in Box N is the unchanged quantity.
LCM of 2 and 5 is 10.
Number of lemons that Jen transferred from Box M to Box N
= 6 u
= 6 x 27
= 162
Increase in the number of lemons that due to the transfer from Box M to Box N
= 14 p - 5 p
= 9 p
9 p = 6 u
9 p = 162
1 p = 162 ÷ 9 = 18
Number of fruits in Box N in the end
= 10 p + 14 p
= 24 p
= 24 x 18
= 432
Answer(s): 432