Irene had some passion fruits and chikoos in 2 baskets. In Basket Y, the number of passion fruits to the number of chikoos was in the ratio of 5 : 9. In Basket Z, there were four times as many passion fruits as chikoos. After Irene transferred ¹₃ of the chikoos from Basket Y to Basket Z, the number of fruits left in Basket Y was 275 and the ratio of the number of passion fruits to the number of chikoos in Basket B became 3 : 7. How many fruits were in Basket Z in the end?

	Basket Y		Basket Z
	Passion Fruits	Chikoos	Passion Fruits	Chikoos
Before	5 u	9 u	4x3 =  12 p	1x3 = 3 p
Change		- 3 u		+ 3 u (+ 25 p)
After	5 u	6 u	3x4 = 12 p	7x4 = 28 p

Number of chikoos that Irene transferred from Basket Y to Basket Z
= ¹₃ x 9 u
= 3 u

Total number of fruits in Basket Y in the end
= 5 u + 6 u
= 11 u

11 u = 275
1 u = 275 ÷ 11 = 25

The number of passion fruits in Basket Z is the unchanged quantity.
LCM of 4 and 3 is 12.

Number of chikoos that Irene transferred from Basket Y to Basket Z
= 3 u
= 3 x 25
= 75

Increase in the number of chikoos that due to the transfer from Basket Y to Basket Z
= 28 p - 3 p
= 25 p

25 p = 3 u 
25 p = 75

1 p = 75 ÷ 25 = 3

Number of fruits in Basket Z in the end
= 12 p + 28 p
= 40 p
= 40 x 3
= 120

Answer(s): 120