Emily had some passion fruits and chikoos in 2 containers. In Container Y, the number of passion fruits to the number of chikoos was in the ratio of 5 : 9. In Container Z, there were five times as many passion fruits as chikoos. After Emily transferred ²₃ of the chikoos from Container Y to Container Z, the number of fruits left in Container Y was 232 and the ratio of the number of passion fruits to the number of chikoos in Container B became 1 : 6. How many fruits were in Container Z in the end?

	Container Y		Container Z
	Passion Fruits	Chikoos	Passion Fruits	Chikoos
Before	5 u	9 u	5x1 =  5 p	1x1 = 1 p
Change		- 6 u		+ 6 u (+ 29 p)
After	5 u	3 u	1x5 = 5 p	6x5 = 30 p

Number of chikoos that Emily transferred from Container Y to Container Z
= ²₃ x 9 u
= 6 u

Total number of fruits in Container Y in the end
= 5 u + 3 u
= 8 u

8 u = 232
1 u = 232 ÷ 8 = 29

The number of passion fruits in Container Z is the unchanged quantity.
LCM of 5 and 1 is 5.

Number of chikoos that Emily transferred from Container Y to Container Z
= 6 u
= 6 x 29
= 174

Increase in the number of chikoos that due to the transfer from Container Y to Container Z
= 30 p - 1 p
= 29 p

29 p = 6 u 
29 p = 174

1 p = 174 ÷ 29 = 6

Number of fruits in Container Z in the end
= 5 p + 30 p
= 35 p
= 35 x 6
= 210

Answer(s): 210