Risa had some chikoos and oranges in 2 cartons. In Carton B, the number of chikoos to the number of oranges was in the ratio of 5 : 6. In Carton C, there were thrice as many chikoos as oranges. After Risa transferred ¹₃ of the oranges from Carton B to Carton C, the number of fruits left in Carton B was 342 and the ratio of the number of chikoos to the number of oranges in Carton B became 2 : 7. How many fruits were in Carton C in the end?

	Carton B		Carton C
	Chikoos	Oranges	Chikoos	Oranges
Before	5 u	6 u	3x2 =  6 p	1x2 = 2 p
Change		- 2 u		+ 2 u (+ 19 p)
After	5 u	4 u	2x3 = 6 p	7x3 = 21 p

Number of oranges that Risa transferred from Carton B to Carton C
= ¹₃ x 6 u
= 2 u

Total number of fruits in Carton B in the end
= 5 u + 4 u
= 9 u

9 u = 342
1 u = 342 ÷ 9 = 38

The number of chikoos in Carton C is the unchanged quantity.
LCM of 3 and 2 is 6.

Number of oranges that Risa transferred from Carton B to Carton C
= 2 u
= 2 x 38
= 76

Increase in the number of oranges that due to the transfer from Carton B to Carton C
= 21 p - 2 p
= 19 p

19 p = 2 u 
19 p = 76

1 p = 76 ÷ 19 = 4

Number of fruits in Carton C in the end
= 6 p + 21 p
= 27 p
= 27 x 4
= 108

Answer(s): 108