Opal had some chikoos and mangosteens in 2 baskets. In Basket K, the number of chikoos to the number of mangosteens was in the ratio of 3 : 8. In Basket L, there were twice as many chikoos as mangosteens. After Opal transferred
34 of the mangosteens from Basket K to Basket L, the number of fruits left in Basket K was 195 and the ratio of the number of chikoos to the number of mangosteens in Basket B became 5 : 9. How many fruits were in Basket L in the end?
|
Basket K |
Basket L |
|
Chikoos |
Mangosteens |
Chikoos |
Mangosteens |
Before |
3 u |
8 u |
2x5 = 10 p |
1x5 = 5 p |
Change |
|
- 6 u |
|
+ 6 u (+ 13 p) |
After |
3 u |
2 u |
5x2 = 10 p |
9x2 = 18 p |
Number of mangosteens that Opal transferred from Basket K to Basket L
=
34 x 8 u
= 6 u
Total number of fruits in Basket K in the end
= 3 u + 2 u
= 5 u
5 u = 195
1 u = 195 ÷ 5 = 39
The number of chikoos in Basket L is the unchanged quantity.
LCM of 2 and 5 is 10.
Number of mangosteens that Opal transferred from Basket K to Basket L
= 6 u
= 6 x 39
= 234
Increase in the number of mangosteens that due to the transfer from Basket K to Basket L
= 18 p - 5 p
= 13 p
13 p = 6 u
13 p = 234
1 p = 234 ÷ 13 = 18
Number of fruits in Basket L in the end
= 10 p + 18 p
= 28 p
= 28 x 18
= 504
Answer(s): 504