Shiyun had some kiwis and persimmons in 2 cartons. In Carton M, the number of kiwis to the number of persimmons was in the ratio of 5 : 9. In Carton N, there were twice as many kiwis as persimmons. After Shiyun transferred ¹₃ of the persimmons from Carton M to Carton N, the number of fruits left in Carton M was 308 and the ratio of the number of kiwis to the number of persimmons in Carton B became 5 : 6. How many fruits were in Carton N in the end?

	Carton M		Carton N
	Kiwis	Persimmons	Kiwis	Persimmons
Before	5 u	9 u	2x5 =  10 p	1x5 = 5 p
Change		- 3 u		+ 3 u (+ 7 p)
After	5 u	6 u	5x2 = 10 p	6x2 = 12 p

Number of persimmons that Shiyun transferred from Carton M to Carton N
= ¹₃ x 9 u
= 3 u

Total number of fruits in Carton M in the end
= 5 u + 6 u
= 11 u

11 u = 308
1 u = 308 ÷ 11 = 28

The number of kiwis in Carton N is the unchanged quantity.
LCM of 2 and 5 is 10.

Number of persimmons that Shiyun transferred from Carton M to Carton N
= 3 u
= 3 x 28
= 84

Increase in the number of persimmons that due to the transfer from Carton M to Carton N
= 12 p - 5 p
= 7 p

7 p = 3 u 
7 p = 84

1 p = 84 ÷ 7 = 12

Number of fruits in Carton N in the end
= 10 p + 12 p
= 22 p
= 22 x 12
= 264

Answer(s): 264