Gwen had some pomegranates and oranges in 2 baskets. In Basket J, the number of pomegranates to the number of oranges was in the ratio of 2 : 9. In Basket K, there were four times as many pomegranates as oranges. After Gwen transferred
13 of the oranges from Basket J to Basket K, the number of fruits left in Basket J was 208 and the ratio of the number of pomegranates to the number of oranges in Basket B became 3 : 4. How many fruits were in Basket K in the end?
|
Basket J |
Basket K |
|
Pomegranates |
Oranges |
Pomegranates |
Oranges |
Before |
2 u |
9 u |
4x3 = 12 p |
1x3 = 3 p |
Change |
|
- 3 u |
|
+ 3 u (+ 13 p) |
After |
2 u |
6 u |
3x4 = 12 p |
4x4 = 16 p |
Number of oranges that Gwen transferred from Basket J to Basket K
=
13 x 9 u
= 3 u
Total number of fruits in Basket J in the end
= 2 u + 6 u
= 8 u
8 u = 208
1 u = 208 ÷ 8 = 26
The number of pomegranates in Basket K is the unchanged quantity.
LCM of 4 and 3 is 12.
Number of oranges that Gwen transferred from Basket J to Basket K
= 3 u
= 3 x 26
= 78
Increase in the number of oranges that due to the transfer from Basket J to Basket K
= 16 p - 3 p
= 13 p
13 p = 3 u
13 p = 78
1 p = 78 ÷ 13 = 6
Number of fruits in Basket K in the end
= 12 p + 16 p
= 28 p
= 28 x 6
= 168
Answer(s): 168