Roshel had some pears and mangoes in 2 boxes. In Box K, the number of pears to the number of mangoes was in the ratio of 2 : 9. In Box L, there were thrice as many pears as mangoes. After Roshel transferred
13 of the mangoes from Box K to Box L, the number of fruits left in Box K was 264 and the ratio of the number of pears to the number of mangoes in Box B became 1 : 4. How many fruits were in Box L in the end?
|
Box K |
Box L |
|
Pears |
Mangoes |
Pears |
Mangoes |
Before |
2 u |
9 u |
3x1 = 3 p |
1x1 = 1 p |
Change |
|
- 3 u |
|
+ 3 u (+ 11 p) |
After |
2 u |
6 u |
1x3 = 3 p |
4x3 = 12 p |
Number of mangoes that Roshel transferred from Box K to Box L
=
13 x 9 u
= 3 u
Total number of fruits in Box K in the end
= 2 u + 6 u
= 8 u
8 u = 264
1 u = 264 ÷ 8 = 33
The number of pears in Box L is the unchanged quantity.
LCM of 3 and 1 is 3.
Number of mangoes that Roshel transferred from Box K to Box L
= 3 u
= 3 x 33
= 99
Increase in the number of mangoes that due to the transfer from Box K to Box L
= 12 p - 1 p
= 11 p
11 p = 3 u
11 p = 99
1 p = 99 ÷ 11 = 9
Number of fruits in Box L in the end
= 3 p + 12 p
= 15 p
= 15 x 9
= 135
Answer(s): 135