Irene had some lemons and starfruits in 2 baskets. In Basket X, the number of lemons to the number of starfruits was in the ratio of 3 : 10. In Basket Y, there were twice as many lemons as starfruits. After Irene transferred
35 of the starfruits from Basket X to Basket Y, the number of fruits left in Basket X was 196 and the ratio of the number of lemons to the number of starfruits in Basket B became 5 : 6. How many fruits were in Basket Y in the end?
|
Basket X |
Basket Y |
|
Lemons |
Starfruits |
Lemons |
Starfruits |
Before |
3 u |
10 u |
2x5 = 10 p |
1x5 = 5 p |
Change |
|
- 6 u |
|
+ 6 u (+ 7 p) |
After |
3 u |
4 u |
5x2 = 10 p |
6x2 = 12 p |
Number of starfruits that Irene transferred from Basket X to Basket Y
=
35 x 10 u
= 6 u
Total number of fruits in Basket X in the end
= 3 u + 4 u
= 7 u
7 u = 196
1 u = 196 ÷ 7 = 28
The number of lemons in Basket Y is the unchanged quantity.
LCM of 2 and 5 is 10.
Number of starfruits that Irene transferred from Basket X to Basket Y
= 6 u
= 6 x 28
= 168
Increase in the number of starfruits that due to the transfer from Basket X to Basket Y
= 12 p - 5 p
= 7 p
7 p = 6 u
7 p = 168
1 p = 168 ÷ 7 = 24
Number of fruits in Basket Y in the end
= 10 p + 12 p
= 22 p
= 22 x 24
= 528
Answer(s): 528