Nicole had some apples and kiwis in 2 crates. In Crate G, the number of apples to the number of kiwis was in the ratio of 5 : 8. In Crate H, there were twice as many apples as kiwis. After Nicole transferred
34 of the kiwis from Crate G to Crate H, the number of fruits left in Crate G was 147 and the ratio of the number of apples to the number of kiwis in Crate B became 5 : 6. How many fruits were in Crate H in the end?
|
Crate G |
Crate H |
|
Apples |
Kiwis |
Apples |
Kiwis |
Before |
5 u |
8 u |
2x5 = 10 p |
1x5 = 5 p |
Change |
|
- 6 u |
|
+ 6 u (+ 7 p) |
After |
5 u |
2 u |
5x2 = 10 p |
6x2 = 12 p |
Number of kiwis that Nicole transferred from Crate G to Crate H
=
34 x 8 u
= 6 u
Total number of fruits in Crate G in the end
= 5 u + 2 u
= 7 u
7 u = 147
1 u = 147 ÷ 7 = 21
The number of apples in Crate H is the unchanged quantity.
LCM of 2 and 5 is 10.
Number of kiwis that Nicole transferred from Crate G to Crate H
= 6 u
= 6 x 21
= 126
Increase in the number of kiwis that due to the transfer from Crate G to Crate H
= 12 p - 5 p
= 7 p
7 p = 6 u
7 p = 126
1 p = 126 ÷ 7 = 18
Number of fruits in Crate H in the end
= 10 p + 12 p
= 22 p
= 22 x 18
= 396
Answer(s): 396