Irene had some chikoos and passion fruits in 2 boxes. In Box B, the number of chikoos to the number of passion fruits was in the ratio of 4 : 9. In Box C, there were four times as many chikoos as passion fruits. After Irene transferred
13 of the passion fruits from Box B to Box C, the number of fruits left in Box B was 270 and the ratio of the number of chikoos to the number of passion fruits in Box B became 5 : 8. How many fruits were in Box C in the end?
|
Box B |
Box C |
|
Chikoos |
Passion Fruits |
Chikoos |
Passion Fruits |
Before |
4 u |
9 u |
4x5 = 20 p |
1x5 = 5 p |
Change |
|
- 3 u |
|
+ 3 u (+ 27 p) |
After |
4 u |
6 u |
5x4 = 20 p |
8x4 = 32 p |
Number of passion fruits that Irene transferred from Box B to Box C
=
13 x 9 u
= 3 u
Total number of fruits in Box B in the end
= 4 u + 6 u
= 10 u
10 u = 270
1 u = 270 ÷ 10 = 27
The number of chikoos in Box C is the unchanged quantity.
LCM of 4 and 5 is 20.
Number of passion fruits that Irene transferred from Box B to Box C
= 3 u
= 3 x 27
= 81
Increase in the number of passion fruits that due to the transfer from Box B to Box C
= 32 p - 5 p
= 27 p
27 p = 3 u
27 p = 81
1 p = 81 ÷ 27 = 3
Number of fruits in Box C in the end
= 20 p + 32 p
= 52 p
= 52 x 3
= 156
Answer(s): 156