Marion had some persimmons and lemons in 2 baskets. In Basket P, the number of persimmons to the number of lemons was in the ratio of 5 : 6. In Basket Q, there were thrice as many persimmons as lemons. After Marion transferred ²₃ of the lemons from Basket P to Basket Q, the number of fruits left in Basket P was 266 and the ratio of the number of persimmons to the number of lemons in Basket B became 2 : 7. How many fruits were in Basket Q in the end?

	Basket P		Basket Q
	Persimmons	Lemons	Persimmons	Lemons
Before	5 u	6 u	3x2 =  6 p	1x2 = 2 p
Change		- 4 u		+ 4 u (+ 19 p)
After	5 u	2 u	2x3 = 6 p	7x3 = 21 p

Number of lemons that Marion transferred from Basket P to Basket Q
= ²₃ x 6 u
= 4 u

Total number of fruits in Basket P in the end
= 5 u + 2 u
= 7 u

7 u = 266
1 u = 266 ÷ 7 = 38

The number of persimmons in Basket Q is the unchanged quantity.
LCM of 3 and 2 is 6.

Number of lemons that Marion transferred from Basket P to Basket Q
= 4 u
= 4 x 38
= 152

Increase in the number of lemons that due to the transfer from Basket P to Basket Q
= 21 p - 2 p
= 19 p

19 p = 4 u 
19 p = 152

1 p = 152 ÷ 19 = 8

Number of fruits in Basket Q in the end
= 6 p + 21 p
= 27 p
= 27 x 8
= 216

Answer(s): 216