Barbara had some kiwis and chikoos in 2 crates. In Crate E, the number of kiwis to the number of chikoos was in the ratio of 5 : 6. In Crate F, there were twice as many kiwis as chikoos. After Barbara transferred ²₃ of the chikoos from Crate E to Crate F, the number of fruits left in Crate E was 77 and the ratio of the number of kiwis to the number of chikoos in Crate B became 3 : 7. How many fruits were in Crate F in the end?

	Crate E		Crate F
	Kiwis	Chikoos	Kiwis	Chikoos
Before	5 u	6 u	2x3 =  6 p	1x3 = 3 p
Change		- 4 u		+ 4 u (+ 11 p)
After	5 u	2 u	3x2 = 6 p	7x2 = 14 p

Number of chikoos that Barbara transferred from Crate E to Crate F
= ²₃ x 6 u
= 4 u

Total number of fruits in Crate E in the end
= 5 u + 2 u
= 7 u

7 u = 77
1 u = 77 ÷ 7 = 11

The number of kiwis in Crate F is the unchanged quantity.
LCM of 2 and 3 is 6.

Number of chikoos that Barbara transferred from Crate E to Crate F
= 4 u
= 4 x 11
= 44

Increase in the number of chikoos that due to the transfer from Crate E to Crate F
= 14 p - 3 p
= 11 p

11 p = 4 u 
11 p = 44

1 p = 44 ÷ 11 = 4

Number of fruits in Crate F in the end
= 6 p + 14 p
= 20 p
= 20 x 4
= 80

Answer(s): 80