Xylia had some lemons and mangoes in 2 baskets. In Basket A, the number of lemons to the number of mangoes was in the ratio of 5 : 9. In Basket B, there were twice as many lemons as mangoes. After Xylia transferred
23 of the mangoes from Basket A to Basket B, the number of fruits left in Basket A was 248 and the ratio of the number of lemons to the number of mangoes in Basket B became 4 : 5. How many fruits were in Basket B in the end?
|
Basket A |
Basket B |
|
Lemons |
Mangoes |
Lemons |
Mangoes |
Before |
5 u |
9 u |
2x2 = 4 p |
1x2 = 2 p |
Change |
|
- 6 u |
|
+ 6 u (+ 3 p) |
After |
5 u |
3 u |
4x1 = 4 p |
5x1 = 5 p |
Number of mangoes that Xylia transferred from Basket A to Basket B
=
23 x 9 u
= 6 u
Total number of fruits in Basket A in the end
= 5 u + 3 u
= 8 u
8 u = 248
1 u = 248 ÷ 8 = 31
The number of lemons in Basket B is the unchanged quantity.
LCM of 2 and 4 is 4.
Number of mangoes that Xylia transferred from Basket A to Basket B
= 6 u
= 6 x 31
= 186
Increase in the number of mangoes that due to the transfer from Basket A to Basket B
= 5 p - 2 p
= 3 p
3 p = 6 u
3 p = 186
1 p = 186 ÷ 3 = 62
Number of fruits in Basket B in the end
= 4 p + 5 p
= 9 p
= 9 x 62
= 558
Answer(s): 558