Jean had some passion fruits and starfruits in 2 containers. In Container V, the number of passion fruits to the number of starfruits was in the ratio of 3 : 10. In Container W, there were twice as many passion fruits as starfruits. After Jean transferred ²₅ of the starfruits from Container V to Container W, the number of fruits left in Container V was 90 and the ratio of the number of passion fruits to the number of starfruits in Container B became 6 : 7. How many fruits were in Container W in the end?

	Container V		Container W
	Passion Fruits	Starfruits	Passion Fruits	Starfruits
Before	3 u	10 u	2x3 =  6 p	1x3 = 3 p
Change		- 4 u		+ 4 u (+ 4 p)
After	3 u	6 u	6x1 = 6 p	7x1 = 7 p

Number of starfruits that Jean transferred from Container V to Container W
= ²₅ x 10 u
= 4 u

Total number of fruits in Container V in the end
= 3 u + 6 u
= 9 u

9 u = 90
1 u = 90 ÷ 9 = 10

The number of passion fruits in Container W is the unchanged quantity.
LCM of 2 and 6 is 6.

Number of starfruits that Jean transferred from Container V to Container W
= 4 u
= 4 x 10
= 40

Increase in the number of starfruits that due to the transfer from Container V to Container W
= 7 p - 3 p
= 4 p

4 p = 4 u 
4 p = 40

1 p = 40 ÷ 4 = 10

Number of fruits in Container W in the end
= 6 p + 7 p
= 13 p
= 13 x 10
= 130

Answer(s): 130