Julie had some pears and apples in 2 cartons. In Carton N, the number of pears to the number of apples was in the ratio of 3 : 10. In Carton P, there were twice as many pears as apples. After Julie transferred ³₅ of the apples from Carton N to Carton P, the number of fruits left in Carton N was 140 and the ratio of the number of pears to the number of apples in Carton B became 4 : 5. How many fruits were in Carton P in the end?

	Carton N		Carton P
	Pears	Apples	Pears	Apples
Before	3 u	10 u	2x2 =  4 p	1x2 = 2 p
Change		- 6 u		+ 6 u (+ 3 p)
After	3 u	4 u	4x1 = 4 p	5x1 = 5 p

Number of apples that Julie transferred from Carton N to Carton P
= ³₅ x 10 u
= 6 u

Total number of fruits in Carton N in the end
= 3 u + 4 u
= 7 u

7 u = 140
1 u = 140 ÷ 7 = 20

The number of pears in Carton P is the unchanged quantity.
LCM of 2 and 4 is 4.

Number of apples that Julie transferred from Carton N to Carton P
= 6 u
= 6 x 20
= 120

Increase in the number of apples that due to the transfer from Carton N to Carton P
= 5 p - 2 p
= 3 p

3 p = 6 u 
3 p = 120

1 p = 120 ÷ 3 = 40

Number of fruits in Carton P in the end
= 4 p + 5 p
= 9 p
= 9 x 40
= 360

Answer(s): 360