Hazel had some pomegranates and mangoes in 2 crates. In Crate U, the number of pomegranates to the number of mangoes was in the ratio of 2 : 9. In Crate V, there were twice as many pomegranates as mangoes. After Hazel transferred ²₃ of the mangoes from Crate U to Crate V, the number of fruits left in Crate U was 50 and the ratio of the number of pomegranates to the number of mangoes in Crate B became 4 : 5. How many fruits were in Crate V in the end?

	Crate U		Crate V
	Pomegranates	Mangoes	Pomegranates	Mangoes
Before	2 u	9 u	2x2 =  4 p	1x2 = 2 p
Change		- 6 u		+ 6 u (+ 3 p)
After	2 u	3 u	4x1 = 4 p	5x1 = 5 p

Number of mangoes that Hazel transferred from Crate U to Crate V
= ²₃ x 9 u
= 6 u

Total number of fruits in Crate U in the end
= 2 u + 3 u
= 5 u

5 u = 50
1 u = 50 ÷ 5 = 10

The number of pomegranates in Crate V is the unchanged quantity.
LCM of 2 and 4 is 4.

Number of mangoes that Hazel transferred from Crate U to Crate V
= 6 u
= 6 x 10
= 60

Increase in the number of mangoes that due to the transfer from Crate U to Crate V
= 5 p - 2 p
= 3 p

3 p = 6 u 
3 p = 60

1 p = 60 ÷ 3 = 20

Number of fruits in Crate V in the end
= 4 p + 5 p
= 9 p
= 9 x 20
= 180

Answer(s): 180