Penelope had some mangosteens and lemons in 2 boxes. In Box U, the number of mangosteens to the number of lemons was in the ratio of 5 : 8. In Box V, there were five times as many mangosteens as lemons. After Penelope transferred
34 of the lemons from Box U to Box V, the number of fruits left in Box U was 203 and the ratio of the number of mangosteens to the number of lemons in Box B became 1 : 6. How many fruits were in Box V in the end?
|
Box U |
Box V |
|
Mangosteens |
Lemons |
Mangosteens |
Lemons |
Before |
5 u |
8 u |
5x1 = 5 p |
1x1 = 1 p |
Change |
|
- 6 u |
|
+ 6 u (+ 29 p) |
After |
5 u |
2 u |
1x5 = 5 p |
6x5 = 30 p |
Number of lemons that Penelope transferred from Box U to Box V
=
34 x 8 u
= 6 u
Total number of fruits in Box U in the end
= 5 u + 2 u
= 7 u
7 u = 203
1 u = 203 ÷ 7 = 29
The number of mangosteens in Box V is the unchanged quantity.
LCM of 5 and 1 is 5.
Number of lemons that Penelope transferred from Box U to Box V
= 6 u
= 6 x 29
= 174
Increase in the number of lemons that due to the transfer from Box U to Box V
= 30 p - 1 p
= 29 p
29 p = 6 u
29 p = 174
1 p = 174 ÷ 29 = 6
Number of fruits in Box V in the end
= 5 p + 30 p
= 35 p
= 35 x 6
= 210
Answer(s): 210