Cindy had some oranges and kiwis in 2 crates. In Crate Q, the number of oranges to the number of kiwis was in the ratio of 5 : 6. In Crate R, there were four times as many oranges as kiwis. After Cindy transferred
13 of the kiwis from Crate Q to Crate R, the number of fruits left in Crate Q was 135 and the ratio of the number of oranges to the number of kiwis in Crate B became 1 : 4. How many fruits were in Crate R in the end?
|
Crate Q |
Crate R |
|
Oranges |
Kiwis |
Oranges |
Kiwis |
Before |
5 u |
6 u |
4x1 = 4 p |
1x1 = 1 p |
Change |
|
- 2 u |
|
+ 2 u (+ 15 p) |
After |
5 u |
4 u |
1x4 = 4 p |
4x4 = 16 p |
Number of kiwis that Cindy transferred from Crate Q to Crate R
=
13 x 6 u
= 2 u
Total number of fruits in Crate Q in the end
= 5 u + 4 u
= 9 u
9 u = 135
1 u = 135 ÷ 9 = 15
The number of oranges in Crate R is the unchanged quantity.
LCM of 4 and 1 is 4.
Number of kiwis that Cindy transferred from Crate Q to Crate R
= 2 u
= 2 x 15
= 30
Increase in the number of kiwis that due to the transfer from Crate Q to Crate R
= 16 p - 1 p
= 15 p
15 p = 2 u
15 p = 30
1 p = 30 ÷ 15 = 2
Number of fruits in Crate R in the end
= 4 p + 16 p
= 20 p
= 20 x 2
= 40
Answer(s): 40