Roshel had some mangoes and kiwis in 2 baskets. In Basket T, the number of mangoes to the number of kiwis was in the ratio of 3 : 10. In Basket U, there were thrice as many mangoes as kiwis. After Roshel transferred
45 of the kiwis from Basket T to Basket U, the number of fruits left in Basket T was 55 and the ratio of the number of mangoes to the number of kiwis in Basket B became 4 : 5. How many fruits were in Basket U in the end?
|
Basket T |
Basket U |
|
Mangoes |
Kiwis |
Mangoes |
Kiwis |
Before |
3 u |
10 u |
3x4 = 12 p |
1x4 = 4 p |
Change |
|
- 8 u |
|
+ 8 u (+ 11 p) |
After |
3 u |
2 u |
4x3 = 12 p |
5x3 = 15 p |
Number of kiwis that Roshel transferred from Basket T to Basket U
=
45 x 10 u
= 8 u
Total number of fruits in Basket T in the end
= 3 u + 2 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
The number of mangoes in Basket U is the unchanged quantity.
LCM of 3 and 4 is 12.
Number of kiwis that Roshel transferred from Basket T to Basket U
= 8 u
= 8 x 11
= 88
Increase in the number of kiwis that due to the transfer from Basket T to Basket U
= 15 p - 4 p
= 11 p
11 p = 8 u
11 p = 88
1 p = 88 ÷ 11 = 8
Number of fruits in Basket U in the end
= 12 p + 15 p
= 27 p
= 27 x 8
= 216
Answer(s): 216