Rachel had some pomegranates and pears in 2 baskets. In Basket H, the number of pomegranates to the number of pears was in the ratio of 3 : 10. In Basket J, there were four times as many pomegranates as pears. After Rachel transferred ³₅ of the pears from Basket H to Basket J, the number of fruits left in Basket H was 273 and the ratio of the number of pomegranates to the number of pears in Basket B became 2 : 7. How many fruits were in Basket J in the end?

	Basket H		Basket J
	Pomegranates	Pears	Pomegranates	Pears
Before	3 u	10 u	4x1 =  4 p	1x1 = 1 p
Change		- 6 u		+ 6 u (+ 13 p)
After	3 u	4 u	2x2 = 4 p	7x2 = 14 p

Number of pears that Rachel transferred from Basket H to Basket J
= ³₅ x 10 u
= 6 u

Total number of fruits in Basket H in the end
= 3 u + 4 u
= 7 u

7 u = 273
1 u = 273 ÷ 7 = 39

The number of pomegranates in Basket J is the unchanged quantity.
LCM of 4 and 2 is 4.

Number of pears that Rachel transferred from Basket H to Basket J
= 6 u
= 6 x 39
= 234

Increase in the number of pears that due to the transfer from Basket H to Basket J
= 14 p - 1 p
= 13 p

13 p = 6 u 
13 p = 234

1 p = 234 ÷ 13 = 18

Number of fruits in Basket J in the end
= 4 p + 14 p
= 18 p
= 18 x 18
= 324

Answer(s): 324