Min had some passion fruits and chikoos in 2 cartons. In Carton W, the number of passion fruits to the number of chikoos was in the ratio of 3 : 8. In Carton X, there were twice as many passion fruits as chikoos. After Min transferred
34 of the chikoos from Carton W to Carton X, the number of fruits left in Carton W was 110 and the ratio of the number of passion fruits to the number of chikoos in Carton B became 4 : 5. How many fruits were in Carton X in the end?
|
Carton W |
Carton X |
|
Passion Fruits |
Chikoos |
Passion Fruits |
Chikoos |
Before |
3 u |
8 u |
2x2 = 4 p |
1x2 = 2 p |
Change |
|
- 6 u |
|
+ 6 u (+ 3 p) |
After |
3 u |
2 u |
4x1 = 4 p |
5x1 = 5 p |
Number of chikoos that Min transferred from Carton W to Carton X
=
34 x 8 u
= 6 u
Total number of fruits in Carton W in the end
= 3 u + 2 u
= 5 u
5 u = 110
1 u = 110 ÷ 5 = 22
The number of passion fruits in Carton X is the unchanged quantity.
LCM of 2 and 4 is 4.
Number of chikoos that Min transferred from Carton W to Carton X
= 6 u
= 6 x 22
= 132
Increase in the number of chikoos that due to the transfer from Carton W to Carton X
= 5 p - 2 p
= 3 p
3 p = 6 u
3 p = 132
1 p = 132 ÷ 3 = 44
Number of fruits in Carton X in the end
= 4 p + 5 p
= 9 p
= 9 x 44
= 396
Answer(s): 396