Dana had some mangoes and starfruits in 2 boxes. In Box Y, the number of mangoes to the number of starfruits was in the ratio of 5 : 9. In Box Z, there were thrice as many mangoes as starfruits. After Dana transferred
23 of the starfruits from Box Y to Box Z, the number of fruits left in Box Y was 184 and the ratio of the number of mangoes to the number of starfruits in Box B became 4 : 9. How many fruits were in Box Z in the end?
|
Box Y |
Box Z |
|
Mangoes |
Starfruits |
Mangoes |
Starfruits |
Before |
5 u |
9 u |
3x4 = 12 p |
1x4 = 4 p |
Change |
|
- 6 u |
|
+ 6 u (+ 23 p) |
After |
5 u |
3 u |
4x3 = 12 p |
9x3 = 27 p |
Number of starfruits that Dana transferred from Box Y to Box Z
=
23 x 9 u
= 6 u
Total number of fruits in Box Y in the end
= 5 u + 3 u
= 8 u
8 u = 184
1 u = 184 ÷ 8 = 23
The number of mangoes in Box Z is the unchanged quantity.
LCM of 3 and 4 is 12.
Number of starfruits that Dana transferred from Box Y to Box Z
= 6 u
= 6 x 23
= 138
Increase in the number of starfruits that due to the transfer from Box Y to Box Z
= 27 p - 4 p
= 23 p
23 p = 6 u
23 p = 138
1 p = 138 ÷ 23 = 6
Number of fruits in Box Z in the end
= 12 p + 27 p
= 39 p
= 39 x 6
= 234
Answer(s): 234