Olivia had some apples and chikoos in 2 containers. In Container V, the number of apples to the number of chikoos was in the ratio of 5 : 8. In Container W, there were thrice as many apples as chikoos. After Olivia transferred
34 of the chikoos from Container V to Container W, the number of fruits left in Container V was 196 and the ratio of the number of apples to the number of chikoos in Container B became 1 : 5. How many fruits were in Container W in the end?
|
Container V |
Container W |
|
Apples |
Chikoos |
Apples |
Chikoos |
Before |
5 u |
8 u |
3x1 = 3 p |
1x1 = 1 p |
Change |
|
- 6 u |
|
+ 6 u (+ 14 p) |
After |
5 u |
2 u |
1x3 = 3 p |
5x3 = 15 p |
Number of chikoos that Olivia transferred from Container V to Container W
=
34 x 8 u
= 6 u
Total number of fruits in Container V in the end
= 5 u + 2 u
= 7 u
7 u = 196
1 u = 196 ÷ 7 = 28
The number of apples in Container W is the unchanged quantity.
LCM of 3 and 1 is 3.
Number of chikoos that Olivia transferred from Container V to Container W
= 6 u
= 6 x 28
= 168
Increase in the number of chikoos that due to the transfer from Container V to Container W
= 15 p - 1 p
= 14 p
14 p = 6 u
14 p = 168
1 p = 168 ÷ 14 = 12
Number of fruits in Container W in the end
= 3 p + 15 p
= 18 p
= 18 x 12
= 216
Answer(s): 216