Victoria had some kiwis and oranges in 2 containers. In Container G, the number of kiwis to the number of oranges was in the ratio of 4 : 9. In Container H, there were twice as many kiwis as oranges. After Victoria transferred ¹₃ of the oranges from Container G to Container H, the number of fruits left in Container G was 190 and the ratio of the number of kiwis to the number of oranges in Container B became 4 : 5. How many fruits were in Container H in the end?

	Container G		Container H
	Kiwis	Oranges	Kiwis	Oranges
Before	4 u	9 u	2x2 =  4 p	1x2 = 2 p
Change		- 3 u		+ 3 u (+ 3 p)
After	4 u	6 u	4x1 = 4 p	5x1 = 5 p

Number of oranges that Victoria transferred from Container G to Container H
= ¹₃ x 9 u
= 3 u

Total number of fruits in Container G in the end
= 4 u + 6 u
= 10 u

10 u = 190
1 u = 190 ÷ 10 = 19

The number of kiwis in Container H is the unchanged quantity.
LCM of 2 and 4 is 4.

Number of oranges that Victoria transferred from Container G to Container H
= 3 u
= 3 x 19
= 57

Increase in the number of oranges that due to the transfer from Container G to Container H
= 5 p - 2 p
= 3 p

3 p = 3 u 
3 p = 57

1 p = 57 ÷ 3 = 19

Number of fruits in Container H in the end
= 4 p + 5 p
= 9 p
= 9 x 19
= 171

Answer(s): 171