Linda had some mangoes and pomegranates in 2 containers. In Container G, the number of mangoes to the number of pomegranates was in the ratio of 2 : 9. In Container H, there were twice as many mangoes as pomegranates. After Linda transferred
23 of the pomegranates from Container G to Container H, the number of fruits left in Container G was 135 and the ratio of the number of mangoes to the number of pomegranates in Container B became 7 : 8. How many fruits were in Container H in the end?
|
Container G |
Container H |
|
Mangoes |
Pomegranates |
Mangoes |
Pomegranates |
Before |
2 u |
9 u |
2x7 = 14 p |
1x7 = 7 p |
Change |
|
- 6 u |
|
+ 6 u (+ 9 p) |
After |
2 u |
3 u |
7x2 = 14 p |
8x2 = 16 p |
Number of pomegranates that Linda transferred from Container G to Container H
=
23 x 9 u
= 6 u
Total number of fruits in Container G in the end
= 2 u + 3 u
= 5 u
5 u = 135
1 u = 135 ÷ 5 = 27
The number of mangoes in Container H is the unchanged quantity.
LCM of 2 and 7 is 14.
Number of pomegranates that Linda transferred from Container G to Container H
= 6 u
= 6 x 27
= 162
Increase in the number of pomegranates that due to the transfer from Container G to Container H
= 16 p - 7 p
= 9 p
9 p = 6 u
9 p = 162
1 p = 162 ÷ 9 = 18
Number of fruits in Container H in the end
= 14 p + 16 p
= 30 p
= 30 x 18
= 540
Answer(s): 540