Dana had some apples and pears in 2 cartons. In Carton T, the number of apples to the number of pears was in the ratio of 4 : 9. In Carton U, there were twice as many apples as pears. After Dana transferred ²₃ of the pears from Carton T to Carton U, the number of fruits left in Carton T was 196 and the ratio of the number of apples to the number of pears in Carton B became 3 : 5. How many fruits were in Carton U in the end?

	Carton T		Carton U
	Apples	Pears	Apples	Pears
Before	4 u	9 u	2x3 =  6 p	1x3 = 3 p
Change		- 6 u		+ 6 u (+ 7 p)
After	4 u	3 u	3x2 = 6 p	5x2 = 10 p

Number of pears that Dana transferred from Carton T to Carton U
= ²₃ x 9 u
= 6 u

Total number of fruits in Carton T in the end
= 4 u + 3 u
= 7 u

7 u = 196
1 u = 196 ÷ 7 = 28

The number of apples in Carton U is the unchanged quantity.
LCM of 2 and 3 is 6.

Number of pears that Dana transferred from Carton T to Carton U
= 6 u
= 6 x 28
= 168

Increase in the number of pears that due to the transfer from Carton T to Carton U
= 10 p - 3 p
= 7 p

7 p = 6 u 
7 p = 168

1 p = 168 ÷ 7 = 24

Number of fruits in Carton U in the end
= 6 p + 10 p
= 16 p
= 16 x 24
= 384

Answer(s): 384