Gem had some mangosteens and chikoos in 2 boxes. In Box M, the number of mangosteens to the number of chikoos was in the ratio of 2 : 9. In Box N, there were twice as many mangosteens as chikoos. After Gem transferred ²₃ of the chikoos from Box M to Box N, the number of fruits left in Box M was 105 and the ratio of the number of mangosteens to the number of chikoos in Box B became 1 : 4. How many fruits were in Box N in the end?

	Box M		Box N
	Mangosteens	Chikoos	Mangosteens	Chikoos
Before	2 u	9 u	2x1 =  2 p	1x1 = 1 p
Change		- 6 u		+ 6 u (+ 7 p)
After	2 u	3 u	1x2 = 2 p	4x2 = 8 p

Number of chikoos that Gem transferred from Box M to Box N
= ²₃ x 9 u
= 6 u

Total number of fruits in Box M in the end
= 2 u + 3 u
= 5 u

5 u = 105
1 u = 105 ÷ 5 = 21

The number of mangosteens in Box N is the unchanged quantity.
LCM of 2 and 1 is 2.

Number of chikoos that Gem transferred from Box M to Box N
= 6 u
= 6 x 21
= 126

Increase in the number of chikoos that due to the transfer from Box M to Box N
= 8 p - 1 p
= 7 p

7 p = 6 u 
7 p = 126

1 p = 126 ÷ 7 = 18

Number of fruits in Box N in the end
= 2 p + 8 p
= 10 p
= 10 x 18
= 180

Answer(s): 180