Jen had some starfruits and chikoos in 2 cartons. In Carton D, the number of starfruits to the number of chikoos was in the ratio of 5 : 9. In Carton E, there were five times as many starfruits as chikoos. After Jen transferred ¹₃ of the chikoos from Carton D to Carton E, the number of fruits left in Carton D was 407 and the ratio of the number of starfruits to the number of chikoos in Carton B became 8 : 9. How many fruits were in Carton E in the end?

	Carton D		Carton E
	Starfruits	Chikoos	Starfruits	Chikoos
Before	5 u	9 u	5x8 =  40 p	1x8 = 8 p
Change		- 3 u		+ 3 u (+ 37 p)
After	5 u	6 u	8x5 = 40 p	9x5 = 45 p

Number of chikoos that Jen transferred from Carton D to Carton E
= ¹₃ x 9 u
= 3 u

Total number of fruits in Carton D in the end
= 5 u + 6 u
= 11 u

11 u = 407
1 u = 407 ÷ 11 = 37

The number of starfruits in Carton E is the unchanged quantity.
LCM of 5 and 8 is 40.

Number of chikoos that Jen transferred from Carton D to Carton E
= 3 u
= 3 x 37
= 111

Increase in the number of chikoos that due to the transfer from Carton D to Carton E
= 45 p - 8 p
= 37 p

37 p = 3 u 
37 p = 111

1 p = 111 ÷ 37 = 3

Number of fruits in Carton E in the end
= 40 p + 45 p
= 85 p
= 85 x 3
= 255

Answer(s): 255