Irene had some chikoos and starfruits in 2 containers. In Container K, the number of chikoos to the number of starfruits was in the ratio of 4 : 9. In Container L, there were twice as many chikoos as starfruits. After Irene transferred
23 of the starfruits from Container K to Container L, the number of fruits left in Container K was 189 and the ratio of the number of chikoos to the number of starfruits in Container B became 7 : 8. How many fruits were in Container L in the end?
|
Container K |
Container L |
|
Chikoos |
Starfruits |
Chikoos |
Starfruits |
Before |
4 u |
9 u |
2x7 = 14 p |
1x7 = 7 p |
Change |
|
- 6 u |
|
+ 6 u (+ 9 p) |
After |
4 u |
3 u |
7x2 = 14 p |
8x2 = 16 p |
Number of starfruits that Irene transferred from Container K to Container L
=
23 x 9 u
= 6 u
Total number of fruits in Container K in the end
= 4 u + 3 u
= 7 u
7 u = 189
1 u = 189 ÷ 7 = 27
The number of chikoos in Container L is the unchanged quantity.
LCM of 2 and 7 is 14.
Number of starfruits that Irene transferred from Container K to Container L
= 6 u
= 6 x 27
= 162
Increase in the number of starfruits that due to the transfer from Container K to Container L
= 16 p - 7 p
= 9 p
9 p = 6 u
9 p = 162
1 p = 162 ÷ 9 = 18
Number of fruits in Container L in the end
= 14 p + 16 p
= 30 p
= 30 x 18
= 540
Answer(s): 540