Julie had some chikoos and kiwis in 2 cartons. In Carton M, the number of chikoos to the number of kiwis was in the ratio of 2 : 9. In Carton N, there were five times as many chikoos as kiwis. After Julie transferred ¹₃ of the kiwis from Carton M to Carton N, the number of fruits left in Carton M was 88 and the ratio of the number of chikoos to the number of kiwis in Carton B became 2 : 7. How many fruits were in Carton N in the end?

	Carton M		Carton N
	Chikoos	Kiwis	Chikoos	Kiwis
Before	2 u	9 u	5x2 =  10 p	1x2 = 2 p
Change		- 3 u		+ 3 u (+ 33 p)
After	2 u	6 u	2x5 = 10 p	7x5 = 35 p

Number of kiwis that Julie transferred from Carton M to Carton N
= ¹₃ x 9 u
= 3 u

Total number of fruits in Carton M in the end
= 2 u + 6 u
= 8 u

8 u = 88
1 u = 88 ÷ 8 = 11

The number of chikoos in Carton N is the unchanged quantity.
LCM of 5 and 2 is 10.

Number of kiwis that Julie transferred from Carton M to Carton N
= 3 u
= 3 x 11
= 33

Increase in the number of kiwis that due to the transfer from Carton M to Carton N
= 35 p - 2 p
= 33 p

33 p = 3 u 
33 p = 33

1 p = 33 ÷ 33 = 1

Number of fruits in Carton N in the end
= 10 p + 35 p
= 45 p
= 45 x 1
= 45

Answer(s): 45