Cathy had some passion fruits and mangosteens in 2 baskets. In Basket E, the number of passion fruits to the number of mangosteens was in the ratio of 2 : 9. In Basket F, there were twice as many passion fruits as mangosteens. After Cathy transferred
13 of the mangosteens from Basket E to Basket F, the number of fruits left in Basket E was 264 and the ratio of the number of passion fruits to the number of mangosteens in Basket B became 7 : 8. How many fruits were in Basket F in the end?
|
Basket E |
Basket F |
|
Passion Fruits |
Mangosteens |
Passion Fruits |
Mangosteens |
Before |
2 u |
9 u |
2x7 = 14 p |
1x7 = 7 p |
Change |
|
- 3 u |
|
+ 3 u (+ 9 p) |
After |
2 u |
6 u |
7x2 = 14 p |
8x2 = 16 p |
Number of mangosteens that Cathy transferred from Basket E to Basket F
=
13 x 9 u
= 3 u
Total number of fruits in Basket E in the end
= 2 u + 6 u
= 8 u
8 u = 264
1 u = 264 ÷ 8 = 33
The number of passion fruits in Basket F is the unchanged quantity.
LCM of 2 and 7 is 14.
Number of mangosteens that Cathy transferred from Basket E to Basket F
= 3 u
= 3 x 33
= 99
Increase in the number of mangosteens that due to the transfer from Basket E to Basket F
= 16 p - 7 p
= 9 p
9 p = 3 u
9 p = 99
1 p = 99 ÷ 9 = 11
Number of fruits in Basket F in the end
= 14 p + 16 p
= 30 p
= 30 x 11
= 330
Answer(s): 330