Mary had some persimmons and mangoes in 2 crates. In Crate L, the number of persimmons to the number of mangoes was in the ratio of 4 : 9. In Crate M, there were twice as many persimmons as mangoes. After Mary transferred
13 of the mangoes from Crate L to Crate M, the number of fruits left in Crate L was 260 and the ratio of the number of persimmons to the number of mangoes in Crate B became 4 : 5. How many fruits were in Crate M in the end?
|
Crate L |
Crate M |
|
Persimmons |
Mangoes |
Persimmons |
Mangoes |
Before |
4 u |
9 u |
2x2 = 4 p |
1x2 = 2 p |
Change |
|
- 3 u |
|
+ 3 u (+ 3 p) |
After |
4 u |
6 u |
4x1 = 4 p |
5x1 = 5 p |
Number of mangoes that Mary transferred from Crate L to Crate M
=
13 x 9 u
= 3 u
Total number of fruits in Crate L in the end
= 4 u + 6 u
= 10 u
10 u = 260
1 u = 260 ÷ 10 = 26
The number of persimmons in Crate M is the unchanged quantity.
LCM of 2 and 4 is 4.
Number of mangoes that Mary transferred from Crate L to Crate M
= 3 u
= 3 x 26
= 78
Increase in the number of mangoes that due to the transfer from Crate L to Crate M
= 5 p - 2 p
= 3 p
3 p = 3 u
3 p = 78
1 p = 78 ÷ 3 = 26
Number of fruits in Crate M in the end
= 4 p + 5 p
= 9 p
= 9 x 26
= 234
Answer(s): 234