Bryan has 5-cent coins and 50-cent coins. The total value of all his coins is $19. He has 5 less 5-cent coins than 50-cent coins. How many coins does he have altogether?
| |
5-cent |
50-cent |
Total |
| Number |
1 u |
1 u + 5 |
2 u + 5 |
| Value |
5 |
50 |
|
| Total value |
5 u |
50 u + 250 |
55 u + 250 |
$1 = 100¢
$19 = 19 x 100 = 1900¢
Bryan has 5 more 50-cent coins than 5-cent coins.
Number of 5-cent coins = 1 u
Number of 50-cent coins = 1 u + 5
Total value of 5-cent coins
= 5 x 1 u
= 5 u
Total value of 50-cent coins
= 50 x (1 u + 5)
= 50 u + 250
Total value of the coins
= 5 u + 50 u + 250
= 55 u + 250
55 u + 250 = 1900
55 u = 1900 - 250
55 u = 1650
1 u = 1650 ÷ 55 = 30
Total number of coins
= 1 u + (1 u + 5)
= 2 u + 5
= 2 x 30 + 5
= 60 + 5
= 65
Answer(s): 65
